Steps to finding derivate of natural log

I have the equation to:

P(t)=3000e^((.065)(t))


this is compound interest


The derivate is P'(t)= 195e^((.065)(t))

but I just have the answer. I'm exactly sure how to find the derivate. I need the steps.
HELP ANYONE?

in general the derivative of ae^(bx) = abe^(bx), where a and b are constants
so
P(t)=3000e^((.065)(t))
P'(t)=3000(.065)e^((.065)(t))
P'(t)=195e^((.065)(t))