a country club has found that the number of complete rounds played by a member during a given outing averages 1.3 rounds. What is the probability that a golfer selected at random will complete at least 2 rounds of golf in his or her next outing?
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use the poisson with mean m = 1.3 , and formula
P[x] = e^-m *m^x/x!
P[≥2] = 1 - P[≤1] = 1 - e^-1.3(1 + 1.3 ) = 0.3732 <----
P[x] = e^-m *m^x/x!
P[≥2] = 1 - P[≤1] = 1 - e^-1.3(1 + 1.3 ) = 0.3732 <----