Simplify. t-3 over t^2-5t+6 and 2d^2+12d over d+6

1) t-3 over t^2-5t+6
2) 2d^2+12d over d+6

Show work please!

1st is 1 / [ t - 2 ] , t ╪ 3 while the 2nd is 2d , d ╪ - 6

note: without the ╪3 or -6 the answers would be false...as 1 / [ 3 -2] = 1 ╪ { 3-3} /{ 9 - 15 + 6 } = 0 / 0