Find all degree solutions in the interval 0° ≤ x < 360° for cos(3x)=sqrt3/2

Find all degree solutions in the interval 0° ≤ x < 360° for cos(3x)=sqrt3/2

Answers should be in this format, six answers.
x= ___ °
x= ___ °
x= ___ °
x= ___ °
x= ___ °
x= ___ °

Cos 3x= sqrt3/2,= cos30, cos 330, cos390, cos 690, cos 750, cos 1050
x = 10,
110,
130,
230,
250,
350

:)

cos(3x) = √3/2

3x = 30 + 360k
3x = 330 + 360k, for all integers k

x = 10 + 120k
x = 110 + 120k, for all integers k

For k = 0, 1, 2, we get:

x = 10, 110, 130, 230, 250, 350