Find an expression for the velocity of the train in terms of t? please look at the extra information!
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Find an expression for the velocity of the train in terms of t? please look at the extra information!

[From: ] [author: ] [Date: 12-03-31] [Hit: ]
x(t) = .12t - .0003t^2-v(t) = 0.12t - 0.......
This is the information given in the question:
A train starts from rest at station A and travels to station B where it comes to rest again. The displacement of the train from A at time t (s) after leaving A is x m, where x=0.06t² - 0.0001t³.

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Just take the derivative!!

The derivative of the position (displacement) is velocity.

So...

x(t)= .06t^2 - .0001t^3

x'(t) = .12t - .0003t^2 <== Answer.

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v(t) = 0.12t - 0.0003 t^2 (the derivative of the displacement)
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