Find: ∫( (t^3+2t)/t )dt - Integration help

I tried but i got an odd answer:

∫( (t^3+2t)/t )dt
∫( t^-1(t^3+2t) )dt
∫( t^-3 + 2t^-1 )dt
= t^-2/-2 + 2t^0/0 + c

But then you cant divide by 0 - otherwise the answer would technically be ∞?

Notice that (t^3+2t)/t=t^2+2

Which if you integrate you should get 2t+(t^3)/3+C

You are not integrating right at your last step

1/3 t (6+t^2) + c
Im in cal 1 and just starting integrals, but that looks right to me, i literally just copied and pasted into wolfram alpha. I feel sorry for you if you're this far into calculus and dont know about it, it even shows you the steps, check it out:

http://www.wolframalpha.com/input/?i=+%E2%88%AB%28+%28t%5E3%2B2t%29%2Ft+%29dt

S = integral
Devide by t leaving
S[t^2+2)dt =t^3/3 +2t +k where K where k is a constant

Y U NO ASK TEACHER?!