how do i calculate the probability of tossing a coin 25 times and getting 2 heads?
how do i solve it?
how do i solve it?
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Assuming a fair coin, this is binomial with n=25, p=.5 and #success = 2. The calculation is then:
(25 C 2) * .5^2 * (1-.5)^(25-2), where (25 C 2) means "25 choose 2". This yields:
25*24/(1*2) * .5^25 = .00000894, or about 1/111848.
(25 C 2) * .5^2 * (1-.5)^(25-2), where (25 C 2) means "25 choose 2". This yields:
25*24/(1*2) * .5^25 = .00000894, or about 1/111848.
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Not being mean, but that is like really easy. Try sloving this.(my homework)
Sqaure root of 62-18 + -43^2 over X
Try and figure it out by yourself. And um, its omfg. not omgf...
Sqaure root of 62-18 + -43^2 over X
Try and figure it out by yourself. And um, its omfg. not omgf...
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so you are saying out of the 25 you only got 2 heads so that means.... 2/25 or 8% probability