What are the spherical coordinates of the point whose rectangular coordinates are (3,2,0)

pho =
theta =
psi =

x = ƿ sin ɸ cosθ = 3

y = ƿ sin ɸ sin θ = 2

z = ƿ cos ɸ = 0

ƿ^2 = x^2 + y^2 + z^2

ƿ^2 = 9 + 4 + 0 = 13

ƿ = √13

z = ƿ cos ɸ ==> cos ɸ = z/ƿ = 0 ==> ɸ = π/2

y = ƿ sin ɸ sin θ

=> sin θ = y /ƿ sin ɸ = 2 / √13 = (2/13)√13

θ = sin^-1(2 / √13) = (47 /250)π

spherical coordinates = (√13, (47 /250)π, π/2)

rho = √(3² + 2² + 0²) = √13
theta (from x axis towards y axis) = arctan(2/3) in quadrant I. ≈ 36.69 degrees
psi (from z axis) = 90 degrees

So (3, 2, 0) orthogonal is (√13, 36.69, 90) spherical.

Hmm.. I'm a little confused by your question.. Could you add more details please?