What is the slope, y intercept and x intercept for 2/3y+x=3

PLEASE ANYONE CAN HELP ME!!
Thank you anything can help:)

Dear Ailyn,

(2)/(3)*y+x=3

To find the x-intercept, substitute in 0 for y and solve for x.
(2)/(3)*(0)+x=3

Multiply 2*0 to get 0 in the numerator.
(0)/(3)+x=3

Any expression with a factor of 0 in the numerator is equal to 0.
0+x=3

Combine all similar expressions.
x=3

To find the y-intercept, substitute in 0 for x and solve for y.
(2)/(3)*y+(0)=3

Remove the parentheses around the expression 0.
(2)/(3)*y+0=3

Multiply (2)/(3) by y to get (2y)/(3).
(2y)/(3)+0=3

Remove the 0 from the polynomial; adding or subtracting 0 does not change the value of the expression.
(2y)/(3)=3

Multiply each term in the equation by 3.
2y=9

Solve the equation.
y=(9)/(2)

These are the x and y intercepts of the equation (2)/(3)*y+x=3.
x=3, y=(9)/(2)
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Slope and y intercept
(2)/(3)*y+x=3

Multiply (2)/(3) by y to get (2y)/(3).
(2y)/(3)+x=3

Since x does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting x from both sides.
(2y)/(3)=-x+3

Multiply each term in the equation by 3.
2y=-3x+9

Divide each term in the equation by 2.
y=-(3(x-3))/(2)

Multiply -3 by each term inside the parentheses.
y=(-3x+9)/(2)

Divide each term in the numerator by the denominator.
y=-(3x)/(2)+(9)/(2)

Solve the second equation to setup the y=mx+b formula.
y=mx+b

Using the y=mx+b formula, m=-(3)/(2) and b=(9)/(2).
m=-(3)/(2), b=(9)/(2)
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Thanks

3=2y/3 + x
-x+3 = 2y/3
-3x/2 + 9/2 = y

Slope is -3/2
y-intercept is (0, 9/2)
x-intercept is when y = 0:
-3x/2 + 9/2 = 0
-3x/2 = -9/2
x = (-2/3)(-9/2)
x=3

x-intercept is (3,0)

2y+3x = 9
y = -3x/2 +9/2
Slope = -3/2, y intercept = 9/2, x intercept = 3

The slope for both intercept is -2/3 for the line. Y = -2/3 x +3