Mr. Wilson leaves at 2.5 hours before Mrs. Wilson. If he averages 75 and she averages 85 mph how long would

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HOME > > Mr. Wilson leaves at 2.5 hours before Mrs. Wilson. If he averages 75 and she averages 85 mph how long would

Mr. Wilson leaves at 2.5 hours before Mrs. Wilson. If he averages 75 and she averages 85 mph how long would

[From: ] [author: ] [Date: 12-09-13] [Hit: ]

Time =187.5 /10 = 18.75 hours ANSWER-Mr Wilson travels a total of 187.so she will overtake Mr Wilson in 18.......

will it take Mrs. Wilson to overtake Mr. Wilson? (Hours)

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Their distance will be the same when she catches up with him.
Her time is x, so his is (x + 2.5)

75(x + 2.5) = 85x
75x + 187.5 = 85x
187.5 = 10x
18.75 = x
the time will be 18 hours 45 minutes

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In 2.5 hours Mr Wilson is 2.5 X 75 = 187.5 miles ahead

Net speed of Mrs Wilson = 85-75 = 10mph

Time = 187.5 /10 = 18.75 hours ANSWER

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Mr Wilson travels a total of 187.5 miles before Mrs Wilson leaves

when Mrs Wilson leaves she make up 10 miles per hour

so she will overtake Mr Wilson in 18.75 hours which is 18 hours and 45 min

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