4% of people in a population of 600,000 are vegan. 300 people are going to a restaurant. If there are 14 vegan meals available, then what is the probability that 15 or more of the people in the restaurant will be vegan?
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binomdist with n = 300, p 0.04, q = 0.96
P[k] = 300Ck *0.04^k *0.96^(300-k)
P[≥15] = 1 - P[≤14]
= 1 - sum of 300Ck *0.04^k *0.96^(300-k) for k = 0 to 14 = 0.2242 <--------
note:
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btw, there being 14 meals available has nothing to do with P[≥15 vegan]
P[k] = 300Ck *0.04^k *0.96^(300-k)
P[≥15] = 1 - P[≤14]
= 1 - sum of 300Ck *0.04^k *0.96^(300-k) for k = 0 to 14 = 0.2242 <--------
note:
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btw, there being 14 meals available has nothing to do with P[≥15 vegan]
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Pretty unlikely..