Which of the following is the simplified form of (x^2-9)/(x+3)

x – 3, with the restriction x ≠ –3

x + 3, with the restriction x ≠ –3

x – 3, with the restriction x ≠ 3

x + 3, with the restriction x ≠ 3

the first answer is the correct choice since if x was -3, the denominator of the original expression would be zero which is a bad thing

x^2 - 9 is known as a difference of squares (x^2 is a square and 9 is a square)

so, it factors to (x+3)(x-3)

when you divide that by (x+3),
you are left with (x-3)

We can't have a denominator = 0 because that is dividing by zero which is undefined, so x cannot be -3

The answer is the first one.

x – 3, with the restriction x ≠ –3

hint:
a^2-b^2=(a-b)(a+b)