How to find the square root of -832

I know it has to do with i but I'm confused

8√13i

You can have a square root of e negative number, but it isn't a real number. "i" is √-1

832/64 is 13

Therefor, √832 = √64 * √13

The √64 is 8

Thus, we arrive at 8√13

But we still have the negative to deal with. Multiplying the answer by √-1 gives us the answer.

8√13i

you have to break down -832 by factors

-832 = -1*832
=-1*2*416
=-1*2*2*208
=-1*2*2*2*104
= -1*2*2*2*2*52
= -1*2*2*2*2*2*26
= -1*2*2*2*2*2*2*13
and that's as simple as you can go

so as of right now it looks like sqrt(-1*2*2*2*2*2*2*13)

so then you lump groups of two 2s together and replace the sqrt of (-1) with i:

i*sqrt(2*2*2*2*2*2*13)
i*2*sqrt(2*2*2*2*13)
i*2*2*sqrt(2*2*13)
i*2*2*2*sqrt(13)

final answer:
6i*squrt(13)