I need help with an algebra problem.

Ok the section is called solving systems using substitution. The directions for the problem says," Graph each system to estimate the solution. Then use substitution to find the exact solution of the system. Here's the problem: y=-x+4 y=2x+6

Here's the problem: y=-x+4 y=2x+6
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You'll have to do the graphing part

yourself. However, since you have them

both in slope y-intrcept form, set them equal.

-x+4 = 2x+6

add x to both sides

4 = 3x + 6

subtract 6 from both sides

-2 = 3x; x = -2/3
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substitute this into y=2x+6 to find y

y = 2(-2/3) + 6; y = -4/3 + 6; y = -4/3 + 18/3;

y = 14/3 or 4 2/3

roots (-2/3, 4 2/3).

You can graph the equations yourself, right? I can't in this message box.

By substitution: y=-x+4 y=2x+6

Since the right sides of both equations equal y, we can jusr set them equal to each other:

-x + 4 = 2x + 6
Get x all on one side:

4 = 3x + 6
-2 = 3x
x = -2/3
Put this value of x back in one of the equations to find y: y = -(-2/3) + 4 = 4 + 2/3 or 14/3

Now use the other equation to check:

y = 2x + 6
14/3 = 2*(-2/3) + 6 = -4/3 + 18/3 = 14/3

It checks.