Physics Kinematic/Newtons 2nd Law problem
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Physics Kinematic/Newtons 2nd Law problem

[From: ] [author: ] [Date: 13-01-23] [Hit: ]
t= .then use your kinematics equations,plug it in and it should look like this: 0m/s = 13m/s +0.the acceleration is -130 m/s.......
Ok so during a collision, a passenger in the front seat of a car accelerates from 13.3m/s(30 mills per hour) to rest in .10s.

What is the acceleration of the passenger?

-
To answer this first write out what your given:
Vi=13 m/s
Vf=0 m/s
A-= ? m/s^2
d= ? m
t= .1 sec

then use your kinematics equations, for this one use vf=vi + a*t
plug it in and it should look like this: 0m/s = 13m/s +0.1*a

solve for a

the acceleration is -130 m/s. It is in the negative direction since you are slowing down
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keywords: Kinematic,nd,problem,Law,Newtons,Physics,Physics Kinematic/Newtons 2nd Law problem
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