The minimum value of f(x)=x^2 +(2/x) on the interval (1/2) </equal x </equal 2 is
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The minimum value of f(x)=x^2 +(2/x) on the interval (1/2) </equal x </equal 2 is

[From: ] [author: ] [Date: 13-01-23] [Hit: ]
C.D.) 4.E.There is a minimum at x = 1 because f (x) changes from - to +-Yep. SO what is your question?......
A.) (1/2)
B.) 1
C.) 3
D.) 4.5
E.) 5

-
f(x) = x² + 2/x

f '(x) = 2x - 2/x²
f '(x) is undefined at x = 0
f '(x) = 0 at x = 1

<..-..1..+...>

There is a minimum at x = 1 because f '(x) changes from - to +

-
Yep. SO what is your question?

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