Take the derivative of f(x) = ln(x^3 + 2x + 5)

Show complete steps please :)

f(x)=In(x^3+2x+5),
f'(x)=1/(x^3+2x+5)*d/dx(x^3+2x+5),
f'(x)=1/(x^3+2x+5)*(3x^2+2),
f'(x)=(3x^2+2)/(x^3+2x+5).
Answer: (3x^2+2)/(x^3+2x+5).

Can someone answer my questions?

Ok firxt when you are doing a problem like this you start with the exponent first then everything else.


x^3=27x When you are doing this x times itself x times 3 = 3x times another 3 = 9x then one more time 9x times 3= 27x then you will had the like terms which would be 27x and 2x after that you will end up with 29x+5

27x+2x=29

29x+5 is your answer