Express the complex number in trigonometric form with 0 θ 2π. (Enter your answer in terms of cis(θ), where cis(θ) = cos(θ) + isin(θ).)
17i=
im soooo lost please help
17i=
im soooo lost please help
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Manipulate our imaginary number into r(cos(θ) + isin(θ)) form:
17i = 0 + 17i = 17(0 + i) = 17(0 + i*1)
cos(θ)=0 and sin(θ)=1 where θ=π/2 in our range so 17i = 17cis(π/2)
17i = 0 + 17i = 17(0 + i) = 17(0 + i*1)
cos(θ)=0 and sin(θ)=1 where θ=π/2 in our range so 17i = 17cis(π/2)