The region bounded by y=e^(2x), y=0, x=-2 ,x=-1 is rotated around the x-axis. Find the volume.??
Favorites|Homepage
Subscriptions | sitemap
HOME > > The region bounded by y=e^(2x), y=0, x=-2 ,x=-1 is rotated around the x-axis. Find the volume.??

The region bounded by y=e^(2x), y=0, x=-2 ,x=-1 is rotated around the x-axis. Find the volume.??

[From: ] [author: ] [Date: 14-02-13] [Hit: ]
......
Please help me!, I'll give 5 star rating

-
Imagine thin disks perpendicular to the x-axis stacked up between x=-2 and x=-1. The radius of each disk is y=e^(2x) and the thickness is dx. The volume of each disk is πy^2 dx. The sum of the volumes of these disks is
π∫e^(4x) dx integrated from x=-2 to x=-1
= (π/4)e^(4x) where x is evaluated from x=-2 to x=-1
= (π/4)(e^(-4)-e^(-8))
1
keywords: axis,volume,around,bounded,is,The,rotated,region,Find,by,the,The region bounded by y=e^(2x), y=0, x=-2 ,x=-1 is rotated around the x-axis. Find the volume.??
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .