A rectangular wire loop (dimensions of h = 14.0 cm and w = 6.00 cm) with resistance R = 4.00 Ω is mounted on a door. The Earth’s magnetic field, BE = 5.83 ·10–5 T, is uniform and perpendicular to the surface of the closed door (the surface is in the xz-plane). At time t = 0, the door is opened (right edge moves toward the y-axis) at a constant rate, with an opening angle of θ(t) = ωt, where ω = 2.67 rad/s. Calculate the magnitude of the current induced in the loop, i(t = 0.200 s).
http://img577.imageshack.us/i/p072figure.png/
http://img577.imageshack.us/i/p072figure.png/
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The induced emf = NBAω*cos(ωt)
so at t = 0.200s then emf = 1*5.83x10^-5*0.14*0.0600*2.67*cos(2.67*0… = 1.13x10^-6V
So I = emf/R = 1.13x10^-6/4.00 = 2.81x10^-7A
so at t = 0.200s then emf = 1*5.83x10^-5*0.14*0.0600*2.67*cos(2.67*0… = 1.13x10^-6V
So I = emf/R = 1.13x10^-6/4.00 = 2.81x10^-7A