A person, driving a golf ball off a tee, gives the ball a velocity of +28 m/s. The mass of the ball is 0.045 kg, and the duration of the impact with the golf club is 6.0 x 10-3 s.
a) What is the momentum of the golf ball after it has been hit?
b) What is the change in momentum of the ball?
FΔt = mvF - mvi FΔt = (0.045kg)(28m/s) – 0 FΔt = 1.26 kg m/s
c) What is the impulse imparted to the ball?
F = mv / t F = (0.045kg)(28m/s) / 6.0x10-3s F = 210 N
d) What is the average force applied to the ball by the club?
F =Δp / Δt F = 1.26kg m/s / 6.0x10-3 F= 210 N
e) If the ball is to have a greater velocity after being struck, should the contact time with the club be shorter or longer?
i got this far but have no idea what to do for the other questions?
a) What is the momentum of the golf ball after it has been hit?
b) What is the change in momentum of the ball?
FΔt = mvF - mvi FΔt = (0.045kg)(28m/s) – 0 FΔt = 1.26 kg m/s
c) What is the impulse imparted to the ball?
F = mv / t F = (0.045kg)(28m/s) / 6.0x10-3s F = 210 N
d) What is the average force applied to the ball by the club?
F =Δp / Δt F = 1.26kg m/s / 6.0x10-3 F= 210 N
e) If the ball is to have a greater velocity after being struck, should the contact time with the club be shorter or longer?
i got this far but have no idea what to do for the other questions?
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a) momentum = mass*velocity = 0.045*28
b) well it was at rest before being struck i.e. velocity = 0 to a velocity = 28 .... looks good
c) impulse = (m*v) / (delta t)... looks good
d)nice
e) shorter... the impulse is divided by time so decreasing the time would yield a greater force exerted on the ball.
b) well it was at rest before being struck i.e. velocity = 0 to a velocity = 28 .... looks good
c) impulse = (m*v) / (delta t)... looks good
d)nice
e) shorter... the impulse is divided by time so decreasing the time would yield a greater force exerted on the ball.
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