A visitor to a lighthouse wishes to determine the height of the tower. She ties a spool of thread to a small rock to make a simple pendulum, which she hangs down the center of a spiral staircase of the tower. The period of oscillation is 9.54 s. What is the height of the tower?
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For a pendulum of length L, the period of small oscillations T is given by:
T = 2 pi sqrt(L/g)
So
L = g * T^2 /(2pi)^2
= 9.81 m/s^2 * (9.54 s)^2 / (2 pi)^2
= 22.6 m
T = 2 pi sqrt(L/g)
So
L = g * T^2 /(2pi)^2
= 9.81 m/s^2 * (9.54 s)^2 / (2 pi)^2
= 22.6 m
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period of pendulum is:
T=2*pi*sqrt(L/g)
g=9.80665*(1 - ( 2 * h / R))
Where h is the altitude, g is gravity, and R is the radius of the earth
T=2*pi*sqrt(L/g)
g=9.80665*(1 - ( 2 * h / R))
Where h is the altitude, g is gravity, and R is the radius of the earth
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yes