In the figure below, the scale on which the 59 kg physicist stands reads 220 N. How long will the cantaloupe take to reach the floor if the physicist drops it (from rest relative to himself) at a height of 2.0 m above the floor?
I have no clue how to do this question.
The figure is this...
http://www.webassign.net/hrw/hrw7_13-19b.gif
Can someone explain to me how this works? Much appreciated.
I have no clue how to do this question.
The figure is this...
http://www.webassign.net/hrw/hrw7_13-19b.gif
Can someone explain to me how this works? Much appreciated.
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what the scale actually says is what the g is in this setting. since F=mg and you know F (220N) and m(59 kg) you get that g=220/59 which is roughly 3.729
with this acceleration you can now calculate how long it will take for the thing to reach the floor.
d=gt^2/2
t=sqrt(2d/g)
t=1.036s
with this acceleration you can now calculate how long it will take for the thing to reach the floor.
d=gt^2/2
t=sqrt(2d/g)
t=1.036s