the coefficient of kinetic friction between a 780-newton crate and a level warehouse floor is 0.200. calculate the magnitude of the horizontal force required to move the crate across the floor at a constant speed.
how do i do this?!?!
how do i do this?!?!
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Here is the equation you need:
f=(mu)*N
Where, f is the force of friction, mu is the coefficient of friction and N is the normal force.
The Normal force is the force the ground pushes on the crate with, so for a flat surface it is equal to the weight of the crate.
You also need to realize that F=m*a, force is equal to mass times acceleration. so if you want an object to not accelerate, move at constant speed, you have to act on it with zero net force.
Therefore you have to push the crate with exactly the same force caused by the friction.
f=(mu)*N
Where, f is the force of friction, mu is the coefficient of friction and N is the normal force.
The Normal force is the force the ground pushes on the crate with, so for a flat surface it is equal to the weight of the crate.
You also need to realize that F=m*a, force is equal to mass times acceleration. so if you want an object to not accelerate, move at constant speed, you have to act on it with zero net force.
Therefore you have to push the crate with exactly the same force caused by the friction.