Physics - "Uniform Circular Motion" Could you please help me
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Physics - "Uniform Circular Motion" Could you please help me

[From: ] [author: ] [Date: 11-04-22] [Hit: ]
-frequencyf= 33.3 rev/min = 33.3 rev / 60 s = 0.555 rev /s ;angular velocity ω =2πf = 1.radius r = 0.3 / 2 = 0.......
Find the centripetal acceleration of a dust particle on the edge of a vinyl record, 0.3m in diameter, rotation at 33.3 rev/min.

Please show your working clearly.

THANKYOU!!!! <3

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frequency f = 33.3 rev/min = 33.3 rev / 60 s = 0.555 rev /s ;

angular velocity ω = 2πf = 1.11 π rad /s ;

radius r = 0.3 / 2 = 0.15 m ;

the centripetal acceleration a = r·ω² = 0.15 * 1.11² * π²= 0.184815π² m/s² = 1.824 m/s²
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