The physics of satellite motion around Jupiter.
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The physics of satellite motion around Jupiter.

[From: ] [author: ] [Date: 11-04-22] [Hit: ]
Jupiter has a mass of 1.90 x 1027 kg and a radius of 7.14 x 107 m.a) Determine the radius of motion of the satellite.b) state the force necessary for the satellite to stay in orbit.d) orbital speed-a) r = R + h = 7.......
The physics of satellite motion around Jupiter.
A satellite is placed in orbit 6.00 x 105 m above the surface of Jupiter. Jupiter has a mass of 1.90 x 1027 kg and a radius of 7.14 x 107 m.
a) Determine the radius of motion of the satellite.
b) state the force necessary for the satellite to stay in orbit.
c) direction of the centripetal force
d) orbital speed

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a) r = R + h = 7.14x10^7 + 6.00x10^5 = 7.20x10^7 m

b) F = GMm/r^2 = 6.674x10^-11 * 1.9x10^27 * m / (7.2x10^7)^2 = 24.46*m, where m is the mass of the satellite. (I don't know if they didn't give this to you, or if you just forgot to include it in the question)

c) Towards the center of Jupiter

d) v^2/r = GM/r^2
v = sqrt(GM/r) = sqrt(24.46*7.2x10^7) = 41,967 m/s
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