What are the voltages across the aluminum part and across the copper part

A 10.0 m length of wire consists of 5.0 m of copper followed by 5.0 m of aluminum, both of diameter
1.0 mm. A voltage difference of 69 V is placed across the composite wire.

The total resistance ( I got it) is 0.276. The total current ( i got it) is 250.

For this problem I got the correct answers from the resistivity of copper being 1.68x10^-8 and the resistivity of aluminum being 2.65x10^-8.

Now, the final part requires me to get the voltage across the aluminum and the voltage across the copper separately. I tried using what I have above but I may be doing something incorrectly. Explanation on this part would be helpful.

First find R for each part :

R copper = PL/A = (1.68x10^-8 x 5) / [(0.5^2 x 10^-6) x 3.14] = 0.107 ohms

R Al = (2.65x10^-8 x 5) / [(0.5^2 x 10^-6) x 3.14] = 0.169 ohms

they both sum to 0.276 ohms so u r right about R total

so V copper = I x R copper = 250 x 0.107 = 26.75 V

V Al = I x R al = 250 x 0.169 = 42.25 V