A 1053Welectric toaster operates on a house-
hold circuit of 126 V.
What is the resistance of the wire that
makes up the heating element of the toaster?
Answer in units of Ω.
hold circuit of 126 V.
What is the resistance of the wire that
makes up the heating element of the toaster?
Answer in units of Ω.
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you know P (watts) and V (voltage), so you can work out I (current) using I = P/V (derived from P = IV)
then use the value of I worked out to work out R using R = V/I.
Now, plug the numbers in, I = P / V = 1053 / 126 = 8.36 Amps
and R = V / I = 126 / ( 8.36 ) =15.08 Ohms *Note / is dividing.
There is also a formula you may also consider to do it in one step:
P = V^2 / R so, R = V^2 / P = 126^2 / 1053 = 15.08 Ohms
then use the value of I worked out to work out R using R = V/I.
Now, plug the numbers in, I = P / V = 1053 / 126 = 8.36 Amps
and R = V / I = 126 / ( 8.36 ) =15.08 Ohms *Note / is dividing.
There is also a formula you may also consider to do it in one step:
P = V^2 / R so, R = V^2 / P = 126^2 / 1053 = 15.08 Ohms
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Watts are a measure of Power, and we know that
P(Power)=I(Current)*V(Voltage)
Therefore
1053=I*126
I=8.36 amps
Now that you know Voltage and Current, use Ohm's Law
V=IR
126=8.36*R
R=15.1 ohms
P(Power)=I(Current)*V(Voltage)
Therefore
1053=I*126
I=8.36 amps
Now that you know Voltage and Current, use Ohm's Law
V=IR
126=8.36*R
R=15.1 ohms