A wooden block slides directly down an inclined plane, at a constant velocity of 6.0 m/s. What is the coefficient of kinetic friction, if the plane makes an angle of 25 degrees with the horizontal?
I understand that µ= F/FN which then simplifies to ma/mg, and then a/g, but how do i get the acceleration..?
I understand that µ= F/FN which then simplifies to ma/mg, and then a/g, but how do i get the acceleration..?
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If the velocity is constant, then Newtons first law applies. The acceleration is zero, hence the force is zero.
Fnet = 0
Fg - Ff = 0
Fg = Ff
mgsin25 = ukmgcos25
uk = sin25 / cos25
uk = tan25<-----------Answer (I don't have a calc to finalize)
It turns out you don't even need to know the velocity, as long as it is constant.
Fnet = 0
Fg - Ff = 0
Fg = Ff
mgsin25 = ukmgcos25
uk = sin25 / cos25
uk = tan25<-----------Answer (I don't have a calc to finalize)
It turns out you don't even need to know the velocity, as long as it is constant.