An AC voltage of 50V produces a current of 10mA in a coil .Then the inductive reactance of the coil is
1. 5 Ω, 2. 5 kΩ, 3. 0.5 Ω, 4. 0.2 m Ω
1. 5 Ω, 2. 5 kΩ, 3. 0.5 Ω, 4. 0.2 m Ω
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50 /10e-3 = 5 k Ω
Answer is (2.) 5 k Ω
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Answer is (2.) 5 k Ω
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