You place 3.9 g of water at room temperature in a pressure cooker (a sealed pot) of volume 2.9 L and heat the water to 207 C. What is the pressure in the cooker?
I tried the equation P = nRT
I used 2.9 L for the p, 8.314 for R, 480.15 K for the temperature, and I converted 3.9 g to .216 moles
I go an answer of 298.25 atm so I converted that to Pa because those are the units wanted, and I got 3.01e7 Pa
however, this is wrong and I am not sure what to do from here. Any help would be appreciated!!
I tried the equation P = nRT
I used 2.9 L for the p, 8.314 for R, 480.15 K for the temperature, and I converted 3.9 g to .216 moles
I go an answer of 298.25 atm so I converted that to Pa because those are the units wanted, and I got 3.01e7 Pa
however, this is wrong and I am not sure what to do from here. Any help would be appreciated!!
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Well, using your formula, I got 2.98*10^5 Pa which is 3.02 atm.
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I'm pretty sure the equation is PV=nRT where P is the pressure ur looking for, V is volume, n is number of moles of water u have (so convert 3.9 H2O to moles), use the correct R u find appropriate, and T is temperature. Hope this helps :D