Need help boning up on physics
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Need help boning up on physics

[From: ] [author: ] [Date: 12-07-05] [Hit: ]
G = 6.Q1 = 0.Q2 = 5.F = 6.67 ∙ 4 ∙ 5.6 ∙ 10^-11 ∙ 10^-3 ∙ 10^-5 / 12² = 1.......
Trying to re-learn some physics. In this case, electricity theory.

I just plugged in to the following problem some random numbers -- stationary charges
q1 = .004
q2 = .000056
distance = 12

I got F = 5.5016^ minus 23

Did I even come close, or is the answer unbelievably wrong?

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when solving this kind of problems, you realy need to learn using scientific notation

F = G ∙ Q₁ ∙ Q₂ / r²

G = 6.67 ∙ 10^-11
Q1 = 0.004 = 4 ∙ 10^-3
Q2 = 5.6 ∙ 10^-5
r = 12

F = 6.67 ∙ 4 ∙ 5.6 ∙ 10^-11 ∙ 10^-3 ∙ 10^-5 / 12² = 1.0375 ∙ 10^-19

or

F = 6.67E-11 ∙ 4E-3 ∙ 5.6E-5 / 12² = 1.0375E-19

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I don't have a calculator, but if you used the equation:

E = kQ1*Q2/d...then YES!!!!

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What are the units?
1
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