There are two balls. Ball A has a charge of +1.8 * 10-8 C and Ball B has a charge of
+1.5 * 10-8 C and is 0.002 m away from A.
a. What is the force acting on A?
+1.5 * 10-8 C and is 0.002 m away from A.
a. What is the force acting on A?
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F = q1*q2/4pi(epsilon) r^2
1/4pi(epsilon) = 9x10^9 N*m^2/C^2
F= (9x10^9 N*m^2/C^2) (+1.8 * 10-8 C)(+1.5 * 10-8 C) / 0.002^2
F = .6075 N
1/4pi(epsilon) = 9x10^9 N*m^2/C^2
F= (9x10^9 N*m^2/C^2) (+1.8 * 10-8 C)(+1.5 * 10-8 C) / 0.002^2
F = .6075 N
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use coulomb force