A very long, straight horizontal wire carries a current such that 3.60×1018 electrons per second pass any given point going from west to east. What are the magnitude and direction of the magnetic field this wire produces at a point 4.10 directly above it?
i assumed the number that it gives for charge per second in any given area is the current I, but that was wrong, can anyone give any insight on where to start this problem. THANK YOU!!!
i assumed the number that it gives for charge per second in any given area is the current I, but that was wrong, can anyone give any insight on where to start this problem. THANK YOU!!!
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The current is equal to the electronic charge ( e) * number of electrons per second.
Once you have established this then the magnetism produced ( 2 pi() k I )
Is distributed around the circular path of length 2p() R
i.e 2pi() R B = 2pi() k I
simplify
RB = kI
B = kI/R
= k * e * 3.60 * 10 ^ 18 / R
I can't spot your units for R so I leave you to look up the electronic charge and substitute the value for radius.
Once you have established this then the magnetism produced ( 2 pi() k I )
Is distributed around the circular path of length 2p() R
i.e 2pi() R B = 2pi() k I
simplify
RB = kI
B = kI/R
= k * e * 3.60 * 10 ^ 18 / R
I can't spot your units for R so I leave you to look up the electronic charge and substitute the value for radius.