Physics help please...centripetal acceleration

A conical pendulum is formed by attaching a 60 g mass to a 1.4 m string. The mass swings around a horizontal circle of radius 20 cm.
(a) What is the speed of the mass?

(b) What is the acceleration of the mass?

(c) What is the tension in the string?

The website below has picture of conical pendulum.
http://www.ic.sunysb.edu/Class/phy141md/…

The length of the string is the hypotenuse of a right triangle. The radius of the circle is the side opposite the angle, θ. Radius = 20 cm = 0.2 m
Radius = (length of the string) * sin θ = 1.4 * sin θ
0.2 = 1.4 * sin θ
Sin θ = 0.2/1.4
θ = 8.21321˚

The horizontal component of tension force is directed toward the center of the circle. So, this force is the centripetal force
Ft * sin θ = m * v^2 / r
Mass = 60 g = 0.06 kg, radius = 20 cm = 0.2 m
Ft * 0.2/1.4 = 0.06 * v^2 / 0.2
Multiply both sides by 1.4/0.2
Ft = 1.4/0.2 * 0.06 * v^2 / 0.2
Ft = 2.1 * v^2

The vertical component of tension force is supporting the weight of the object.
Ft * cos θ = m * g
2.1 * v^2 * cos 8.21321˚= 0.06 * 9.8 = 0.588
v^2 = 0.588 ÷ (2.1 * cos 8.21321˚) =
Velocity = √[0.588 ÷ (2.1 * cos 8.21321˚)] = 0.532 m/s
Ft = 2.1 * 0.588 ÷ (2.1 * cos 8.21321˚)
Ft = 0.594 N

Check:
Ft * sin θ = m * v^2 / r
0.594 * sin 8.21321˚ = 0.06 * 0.532^2 / 0.2
0.0849 = 0.0849
The answers for Ft and v are correct.

(a) What is the speed of the mass = 0.532 m/s

(b) What is the acceleration of the mass?
The only acceleration that object has is centripetal acceleration = v^2/r = 0.532^2/0.2

(c) What is the tension in the string? = 0.594 N

I hope this helps understand how to solve this type of problem!

The angle between the string and the vertical = ar sin(0.2/1.4) = 8.21 degrees.
c) T cos(8.21) = mg = 0.06*9.8 => T = 1.68 N
b) a(c) = F(c) / m = T sin(8.21) / 0.06 = 4 m/s^2
a) mv^2/r = T(c) => 0.24 = 0.06v^2 / 0.2 => v = 0.89 m/s