Check chemistry homework (ideal gas law)

Given the following sets of values for three of the gas variables, calculate the unknown quantity.

P=782.4 mm Hg; V=?; n=0.1021 mol; T=26.2 degrees Celsius

I got .0390 L
Is this right? Thanks!!

PV = nRT

(782.4/760) (V) = (0.1021) (0.08206) (299.2)

V = 2.435 L

to three sig figs, 2.44 L

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