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Thermochemistry Help!

[From: ] [author: ] [Date: 11-05-27] [Hit: ]
C = 0.q = 1300 * 0.384 * 206 = 102835.2 J,......
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A skillet made of Copper (Cu) weighing 1.3 kg is heated on a stove to a temperature of 227 oC. If the skillet is removed from the stove and allowed to cool to room temperature (21oC), how much heat must be removed from the skillet. The specific heat of Copper is 0.384 J/(g.oC). kJ

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q = m C dT
m = 1300
C = 0.384
dT = 227 - 21 = 206
q = 1300 * 0.384 * 206 = 102835.2 J, or about 103 kJ
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