Percent Composition of this mixture

I'm confused on this question.

A mixture of gold, zinc and mercy contains 0.225lb of gold, 253g of zinc and 75.0mL of mercury (density =13.6 g/mL). Find the % composition of each of the three metals in the mixture.

Please help.

Percent composition:
%X = (mass of X)/(mass of mixture) * 100%

convert gold lb to mass. Note that lb is a measure of force and not mass, but it can be converted to mass if given gravity (ie. 1 lb is 453 grams on Earth).
.225lb * (453 grams/lb) = 102 grams of gold

253g of zinc = 253 grams of zinc

75mL * (13.6g/mL) = 1020 grams of mercury

total mass = 102 + 253 + 1020 = 1375 grams

======================================…

%X = (mass of X)/(mass of mixture) * 100%

%gold = (102g/1375g) * 100% = 7.4%
%zinc = (253g/1375g) * 100% = 18.4%
%mercury = (1020g/1375g) * 100% = 74.2%

Check your work:
7.4% + 18.4% + 74.2% = 100%

======================================…

Find % composition of bromide in sodium bromide:

%bromide = (79.9g/102.9g) * 100% = 77.6%

X tons of sodium bromide gives 1 ton of bromide

X * 77.6% = 1

X * 0.776 = 1
X = 1/0.776
X = 1.29 tons