Calculating Root Mean square speed
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Calculating Root Mean square speed

[From: ] [author: ] [Date: 11-12-08] [Hit: ]
I know how to do it but I must be messing up somewhere because I keep getting the wrong answer.I solved for V using PV=nRT then I multiplied that which was 112L by 3.74 to get grams and got 418.88g. Then I divided that by 5 mols to get molar mass which was 83.8 g/mol.......
A sample of 5 moles of a gas with a density of 3.74 g/L is
contained in a vessel at STP. What is the root-mean-square
speed of molecules of this gas?

I know how to do it but I must be messing up somewhere because I keep getting the wrong answer.
This is what I did

I solved for V using PV=nRT then I multiplied that which was 112L by 3.74 to get grams and got 418.88g. Then I divided that by 5 mols to get molar mass which was 83.8 g/mol. Now this is where I must mess up. I now calculated the answering using RMS equation which is u = square root of 3RT/M so I did 3 x 8.314 x 273.15K and divided that by 83.8 and then I took the square root of that and I keep getting 9.01 and the answer should be 285m/s what the piss did I do wrong.

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RMS = sqrt(3RT/M)

sqrt( 3 * (8.145 *m^2 * s^-2) * 273) / .0838


~282 m/s


remember to change your grams to kilograms!

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i'm not sure, maybe RMS = sqrt(3RT/M)
sqrt( 3 * (8.145 *m^2 * s^-2) * 273) / .0838
~282 m/s
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keywords: speed,square,Root,Calculating,Mean,Calculating Root Mean square speed
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