How much heat must be absorbed to evaporate 14 g of NH3(ammonia) from liquid to gas state at −33 °C (condensation point)? Heat of condensation for NH3 = 1380 J/g
i have no idea where to even start so please some one explain to me how to do this problem
i have no idea where to even start so please some one explain to me how to do this problem
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Well, all it has to do is boil, so the energy only goes into boiling the ammonia:
q = L * m, where q = heat absorbed or lost, m = mass, L = heat of condensation
q = (1380 J/g) * (14 grams)
q = 19320 Joules is the answer.
q = L * m, where q = heat absorbed or lost, m = mass, L = heat of condensation
q = (1380 J/g) * (14 grams)
q = 19320 Joules is the answer.