A 222mg sample of eugenol was dissolved in 1g chloroform (Kb = 3.63 C/m), increasing the boiling point by 3.68C . What is the molar mass of eugenol?
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delta T = kb x m
m = delta T / kb = 3.68 / 3.63 = 1.014 moles of solute / kg of solvent
we have .222g / 1 g of solvent or 222g / 1000g of solvent
so 1.014 moles = 222 g ;
1 mole has mass of 222 / 1.014 = 218.9 g / mole ... molar mass of eugenol
m = delta T / kb = 3.68 / 3.63 = 1.014 moles of solute / kg of solvent
we have .222g / 1 g of solvent or 222g / 1000g of solvent
so 1.014 moles = 222 g ;
1 mole has mass of 222 / 1.014 = 218.9 g / mole ... molar mass of eugenol