a mass of 60 gram of a metal is heated to 100 C and then placed in 120 gram of water in a calorimeter at 21 C. the temperature of water increases to 32 C
the temperature change of metal is 68C from 100-32
i am confused why though
the temperature change of metal is 68C from 100-32
i am confused why though
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heat lost by metal = heat gained by water
heat = mass x c x ∆T
so, basically what you need to find is the specific heat of the metal
∆T water = 32º final temp - 21º initial temp = 11ºC
60g x c x 68ºC = 120g x 4.184J/gºC x 11ºC
cmetal = 1.35J/gºC
heat = mass x c x ∆T
so, basically what you need to find is the specific heat of the metal
∆T water = 32º final temp - 21º initial temp = 11ºC
60g x c x 68ºC = 120g x 4.184J/gºC x 11ºC
cmetal = 1.35J/gºC
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Sir or Ma'am I think I know the answer to your situation. You are probably confused because you do not know the answer to your question. I hope I helped you out!