How many moles are contained in each of the following at STP

(a) 23.1 L N2

(b) 5.62 L Cl2

(c) 0.114 L Ne

(d) 69.6 mL NH3

1 mol of any ideal gas occupies 22.4 L at STP

Given L x 1 mol/22.4 L

(a) 23.1 L N2 x 1 mol N2/22.4 L N2 = 1.031 mol N2

Sig figs... 1.03 mol N2


(b) 5.62 L Cl2 x 1 mol Cl2/22.4 L Cl2 = 0.2509 mol Cl2

Sig figs... 0.251 mol Cl2


(c) 0.114 L Ne x 1 mol Ne/22.4 L Ne = 0.005089 mol Ne

Sig figs... 0.00509 mol Ne


(d) In this case, we have to convert mL to L first. 1 L = 1000 mL

69.6 mL NH3 x 1 L NH3/1000 mL NH3 x 1 mol NH3/22.4 L NH3 = 0.003107 mol NH3

Sig figs... 0.00311 mol NH3

no. of moles = given volume / molar volume.
(a) = 23.1/22.4 molar volume = 22.4
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