Can you calculate the equilibrium concentrations of H2, N2, & H20

A mixture of 0.10 mol of NO, 0.050 mol of H2, & 0.10 mol of H2O is placed in a 1.0-L vessel at 300 K. The following equilibrium is established:

2NO(g) + 2H2(g) <-------> N2(g) + 2H20 (g)

At equilibrium [NO] = 0.062 M.

Now how the FUUUCK do I determine the equilibrium concentrations of H2, N2, & H20. Thank you so much for your consideration.

0.1 - 2x = 0.062,
x =0.019
[N2] = 0.019,
[H2] = 0.05 - 2x = 0.012
[H2O] = 0.1 + 2x = 0.138