A sample of sulfur hexafluoride gas occupies a volume of 5.10 L at 198°C. Assuming the pressure is constant,

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A sample of sulfur hexafluoride gas occupies a volume of 5.10 L at 198°C. Assuming the pressure is constant,

[From: ] [author: ] [Date: 12-04-16] [Hit: ]

T2 = ?5.10/471 = 2.x = 224.224.42 - 273 = -48.......

what temperature (in °C) is needed to reduce the volume to 2.43 L?

Can't figure it out. Please help! Thank you!

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Charles' Law: V1/T1 = V2/T2

***Temperature MUST BE in Kelvin!!!***

°C -> K

Given °C + 273

V1 = 5.10 L
T1 = 198°C + 273 = 471 K
V2 = 2.43 L
T2 = ?

5.10/471 = 2.43/x
x = 224.42 K

K -> °C

Given K - 273

224.42 - 273 = -48.58°C

Sig figs... -48.6°C

1

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