25ml 0.1 M solution of Ammonium Iron (II) Sulfuric Acid
was titrated by
5ml 0.1 M solution of Potassium Manganate
Moles of Fe(II) = 25ml x 0.1 / 1000
= 0.0025 moles
Moles of MnO4- = 5ml x 0.1 / 1000
= 0.0005 moles
Why is it divided by "1000" to get the concentration of these ions??
If someone can help I would be grateful
was titrated by
5ml 0.1 M solution of Potassium Manganate
Moles of Fe(II) = 25ml x 0.1 / 1000
= 0.0025 moles
Moles of MnO4- = 5ml x 0.1 / 1000
= 0.0005 moles
Why is it divided by "1000" to get the concentration of these ions??
If someone can help I would be grateful
-
They are using the formula:
n (number of moles) = c (concentration) x V (volume in cm^3) / 1000
n = c x (V/1000)
Basically, it is divided by 1000 to convert cm^3, to dm^3, which is the SI (from French: Système international d'unités) unit for volume.
1dm^3 is approximately equivalent to 1 litre.
n (number of moles) = c (concentration) x V (volume in cm^3) / 1000
n = c x (V/1000)
Basically, it is divided by 1000 to convert cm^3, to dm^3, which is the SI (from French: Système international d'unités) unit for volume.
1dm^3 is approximately equivalent to 1 litre.
-
If you want the number of moles, just multiply the molarity by the volume in Litres
KmnO4 Moles = M x L
0.005 x0.1 = 5x10^-3 x1.0x10^-1 5x10^-5 moles
KmnO4 Moles = M x L
0.005 x0.1 = 5x10^-3 x1.0x10^-1 5x10^-5 moles