Calculate the molarity of a solution that contains 36.0g of glucose (C6H12O6) per 2.0L of solution.
i need the work and the answer please! thank you so much!
the 6,12, and 6 are supposed to be subscripts
i need the work and the answer please! thank you so much!
the 6,12, and 6 are supposed to be subscripts
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molar mass of glucose= 6*12+12*1+6*16= 180g/mol
moles glucose= 36.0g/(180g/mol) =0.200
molarity =moles/Liter= 0.2/2.0=0.10 M
moles glucose= 36.0g/(180g/mol) =0.200
molarity =moles/Liter= 0.2/2.0=0.10 M