Please HELP, i have no idea how to do this CHEMISTRY

1. (1 of 3)
A solution contains 0.00758 M HCl.
Determine the [H3O+] for the solution.
Answer in units of M

2. (2 of 3)
Determine the [OH−].
Answer in units of M

3. (3 of 3)
Determine the pH value for the solution.

thx :)

1. Recognize that HCl is a strong acid. This means that it will completely dissociate (exactly 100% dissociation ignoring some ion-pairing effects in solution) into its component ions H+ (which is the same as H3O+) and Cl-. The concentration is easy to determine from this. 1 mole per liter (1 mole per liter equals molarity, M) of HCl will dissociate in solution to give 1 mole of each of its component ions; in other words, to give 1 mole of H+ and 1 mole of Cl-. Therefore, 0.00758 M (M = mole/liter) HCl will dissociate in solution to give 1 mole per liter (M) of each H+ and Cl-. So, [H3O+] = 0.00758 M

2. [H3O+] * [OH-] = 1 x 10^-14 M
(0.00758 M) * [OH-] = 1 x 10^-14 M (Now solve for the unknown, [OH-])
[OH-] = 1.32 x 10^-12 (Conserving significant digits)

3. pH = -log([H3O+)
pH = -log(0.00758)
pH = 2.12