CHEMISTRY HELP PLEASE!! MASS TO MASS CONVERSIONS!!

I am stuck on this one... so here is the equation
Al2O3 + 3C --> 2Al + 3CO

Here is the question...
How many grams of CO will form if 92.1g of Carbon (C) are reacted with an excess of Al2O3?

Please help! 10 points to best answer! Please show work

Hi,

first you have to find how many moles of C is there in 92.1 g of Carbon

Moles of Carbon = 92.1 g * 1 mol / 12.00 g
= 7.675 moles of C

then you have to find the stoichiometric ratio between C and CO ( as you can see in the balanced equation it is C: CO = 3:3)

so amount of moles of CO you will get = 7.675 moles of C *(3 moles of CO / 3 moles of C)
= 7.675 moles of CO

so now you need to find the mass. Simply multiply by the molecular weight of CO
which is (12+16) = 28 g / mol

So mass of CO you would get = 7.675 moles of CO * (28 g of CO / 1 mole of CO)
= 214.9 g of CO

hope I made it clear..:)

ratio from equation 3 to 3
Moles of carbon used = 92.1 / 23 = 7.65 moles of C used which formed 7.65 moles of CO
Mass of CO = 7.65 x 28 =214.9 g