In the reaction below, 98.5 mL of 0.91 M Na2SO4 is reacted with excess AgClO3, what mass of Ag2SO4 is produced?
Na2SO4 + AgClO3 → Ag2SO4 + NaClO3
I tried and tried but couldn't get it plz help):
Na2SO4 + AgClO3 → Ag2SO4 + NaClO3
I tried and tried but couldn't get it plz help):
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Na2SO4 + 2 AgClO3 → Ag2SO4 + 2 NaClO3
(0.0985 L Na2SO4) x (0.91 mol/L) x (1/1) x (311.7997 g Ag2SO4/mol) = 28 g Ag2SO4
(0.0985 L Na2SO4) x (0.91 mol/L) x (1/1) x (311.7997 g Ag2SO4/mol) = 28 g Ag2SO4